Question

Answer 1

\(9999^{10}=\left(99.101\right)^{10}=99^{10}.101^{10}>99^{10}.99^{10}=99^{20}\\ \)

Do đó: \(99^{20}< 9999^{10}\)

Answer 2

`@` `\text {Ans}`

`\downarrow`

`3,`

`a)`

Ta có:

\(99^{20}=\left(99^2\right)^{10}=9801^{10}\)

Vì \(9801< 9999\) `=>`\(9801^{10}< 9999^{10}\)

`=>`\(99^{20}< 9999^{10}\)

Vậy, \(99^{20}< 9999^{10}\)

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`@` Phép nâng lên lũy thừa: `(a^m)^n = a^(m*n)`

`@` `\text {Kaizuu lv uuu}`