Câu hỏi của Thùy Linh Mai

a: BD/CD=AB/AC=3/4=>\(\dfrac{S_{ABD}}{S_{ACD}}=\dfrac{3}{4}\)b: \(BC=\sqrt{12^2+16^2}=20\left(cm\right)\)c: BD/CD=3/4BD+CD=20=>BD=60/7cm; CD=80/7cmd: AH=12*16/20=192/20=9,6cmCâu trả lời: a: BD/CD=AB/AC=3/4=>\(\dfrac{S_{ABD}}{S_{ACD}}=\dfrac{3}{4}\)b: \(BC=\sqrt{12^2+16^2}=20\left(cm\right)\)c: BD/CD=3/4BD+CD=20=>BD=60/7cm; CD=80/7cmd: AH=12*16/20=192/20=9,6cm