Question

Answer 1

`a,`

\(\dfrac{9x-1}{4}=\dfrac{3}{2}\)

`(9x-1)2=4*3`

`(9x-1)2=12`

`9x-1=12 \div 2`

`9x-1=6`

`9x=6+1`

`9x=7`

`-> x=7/9`

`b,`

\(\left(4x+2\right)\div2,5=3,2\div0,5\)

`->` \(\dfrac{4x+2}{2,5}=\dfrac{3,2}{0,5}\)

`-> (4x+2)0,5=2,5*3,2`

`-> (4x+2)0,5=8`

`-> 4x+2=8 \div 5`

`-> 4x+2=8/5`

`-> 4x=8/5 -2`

`-> 4x=-2/5`

`-> x=-2/5 \div 4`

`-> x=-1/10`

`c,`

\(\dfrac{5,4}{x-2}=\dfrac{6}{7}\) 

`-> (x-2)6=5,4*7`

`-> (x-2)6=37,8`

`-> x-2=37,8 \div 6`

`->x-2=6,3`

`-> x=6,3+2`

`-> x=8,3`

`d,`

\(0,5\div2=3\div\left(2x+7\right)\)

`->`\(\dfrac{0,5}{2}=\dfrac{3}{2x+7}\)

`-> (2x+7)0,5=2*3`

`-> (2x+7)0,5=6`

`-> 2x+7=6 \div 0,5`

`-> 2x+7=12`

`-> 2x=12-7`

`-> 2x=5`

`-> x=5/2`

Answer 2

a: =>9x-1=6

=>9x=7

=>x=7/9

b: =>4x+2=6,4*2,5=16

=>4x=14

=>x=7/2

c: =>x-2=6,3

=>x=8,3

d; =>3:(2x+7)=1:4

=>2x+7=12

=>2x=5

=>x=5/2