Question

 

Answer 1

\(e)\dfrac{3x-11}{11}-\dfrac{x}{3}=\dfrac{3x-5}{7}-\dfrac{5x-3}{9}\)

\(\Leftrightarrow\dfrac{3x-11}{11}-\dfrac{x}{3}-\dfrac{3x-5}{7}+\dfrac{5x-3}{9}\)

\(\Leftrightarrow\dfrac{63\left(3x-11\right)-231x-99\left(3x-5\right)+77\left(5x-3\right)}{693}=0\)

\(\Leftrightarrow189x-693-231x-297x+495+385x-231=0\)

\(\Leftrightarrow46x=429\)

\(\Leftrightarrow x=\dfrac{429}{46}\)

Answer 2

f: \(\Leftrightarrow\dfrac{6.3x-4.9-20x+6}{28}=\dfrac{7x-1.1-2+10x}{6}\)

=>6(-13,7x+1,1)=28(17x-3,1)

=>-82,2x+6,6=476x-86,8

=>-558,2x=-93.4

=>x=467/2791