Câu 5:
a, \(C_2H_2+2Br_2\rightarrow C_2H_2Br_4\)
\(n_{Br_2}=\dfrac{16}{160}=0,1\left(mol\right)\)
Theo PT: \(n_{C_2H_2}=n_{C_2H_2Br_4}=\dfrac{1}{2}n_{Br_2}=0,05\left(mol\right)\)
\(\Rightarrow m_{C_2H_2Br_4}=0,05.346=17,3\left(g\right)\)
b, \(V_{C_2H_2}=0,05.22,4=1,12\left(l\right)\) \(\Rightarrow V_{CH_4}=4,48-1,12=3,36\left(l\right)\)
c, \(\left\{{}\begin{matrix}\%V_{CH_4}=\dfrac{3,36}{4,48}.100\%=75\%\\\%V_{C_2H_2}=25\%\end{matrix}\right.\)
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