Question

Answer 1

\(P=\left(\dfrac{2\sqrt{a}\left(\sqrt{a}-3\right)}{\left(\sqrt{a}+3\right)\left(\sqrt{a}-3\right)}+\dfrac{\left(\sqrt{a}+1\right)\left(\sqrt{a}+3\right)}{\left(\sqrt{a}+3\right)\left(\sqrt{a}-3\right)}-\dfrac{7\sqrt{a}+3}{\left(\sqrt{a}-3\right)\left(\sqrt{a}+3\right)}\right).\dfrac{\left(\sqrt{a}+3\right)^2}{\sqrt{a}}\)

\(=\left(\dfrac{2a-6\sqrt{a}+a+4\sqrt{a}+3-7\sqrt{a}-3}{\left(\sqrt{a}-3\right)\left(\sqrt{a}+3\right)}\right).\dfrac{\left(\sqrt{a}+3\right)^2}{\sqrt{a}}\)

\(=\left(\dfrac{3a-9\sqrt{a}}{\left(\sqrt{a}-3\right)\left(\sqrt{a}+3\right)}\right).\dfrac{\left(\sqrt{a}+3\right)^2}{\sqrt{a}}\)

\(=\dfrac{3\sqrt{a}\left(\sqrt{a}-3\right).\left(\sqrt{a}+3\right)^2}{\left(\sqrt{a}-3\right)\left(\sqrt{a}+3\right).\sqrt{a}}=3\left(\sqrt{a}+3\right)\)