Question

Answer 1

\(a,\left(3x+2\right)^2-\left(3x-2\right)^2=5x+38\\ =>\left[\left(3x+2\right)-\left(3x-2\right)\right]\left[\left(3x+2\right)+\left(3x-2\right)\right]=5x+38\\ =>4.6x-5x=38\\ =>24x-5x=38\\ =>19x=38\\ =>x=2\\ b,3\left(x-2\right)^2+9\left(x-1\right)=3\left(x^2+x-3\right)\\ =>3\left(x^2-4x+4\right)+9x-9=3x^2+3x-9\\ =>3x^2-12x+12+9x-9-3x^2-3x+9=0\\ =>-6x+12=0\\ =>-6x=-12\\ =>x=2\)

Answer 2

a: =>9x^2+12x+4-9x^2+12x-4=5x+38

=>24x=5x+38

=>19x=38

=>x=2

b: =>3(x^2-4x+4)+9x-9=3x^2+3x-9

=>3x^2-12x+12+9x-9=3x^2+3x-9

=>3x+3=3x-9

=>Loại