TA có: \(\frac{2^2}{1\cdot3}\cdot\frac{3^2}{2\cdot4}\cdot\ldots\cdot\frac{99^2}{98\cdot100}\)
\(=\frac{2\cdot3\cdot\ldots\cdot99}{1\cdot2\cdot\ldots\cdot98}\cdot\frac{2\cdot3\cdot\ldots\cdot98}{3\cdot4\cdot\ldots\cdot100}\)
\(=\frac{99}{1}\cdot\frac{2}{100}=\frac{99}{50}\)
