a: ĐKXĐ: x<>0
PT =>3x^2+7x-10=0
=>3x^2+10x-3x-10=0
=>(3x+10)(x-1)=0
=>x=1 hoặc x=-10/3
b: ĐKXĐ: x thuộc R
PT =>4x-17=0
=>x=17/4
c: ĐKXĐ: x<>4; x<>2
PT =>(x-2)(x-6)=x(x-4)
=>x^2-8x+12=x^2-4x
=>-8x+12=-4x
=>-4x=-12
=>x=3
d: ĐKXĐ: x<>2; x<>1
PT =>x^2-3x+2+(2x-5)(x-1)-(3x-5)(x-2)=0
=>x^2-3x+2+2x^2-2x-5x+5-(3x^2-6x-5x+10)=0
=>3x^2-10x+7-3x^2+11x-10=0
=>x-3=0
=>x=3
f: \(\Leftrightarrow\left(x-3\right)\left(x-4\right)+\left(x-2\right)^2=-\left(x-2\right)\left(x-4\right)\)
=>\(x^2-7x+12+x^2-4x+4=-\left(x^2-6x+8\right)=-x^2+6x-8\)
=>\(2x^2-11x+16+x^2-6x+8=0\)
=>3x^2-17x+24=0
=>3x^2-9x-8x+24=0
=>(x-3)(3x-8)=0
=>x=8/3 hoặc x=3
i: \(\Leftrightarrow5\left(x-1\right)^2=\left(2x+1\right)\left(x+1\right)\)
=>\(5x^2-10x+5=2x^2+3x+1\)
=>3x^2-13x+4=0
=>3x^2-12x-x+4=0
=>(x-4)(3x-1)=0
=>x=1/3 hoặc x=4
