Question

Answer 1

a) \(B=\left(\dfrac{\sqrt{x}-3}{\sqrt{x}+3}+\dfrac{\sqrt{x}+3}{\sqrt{x}-3}+\dfrac{14}{x-9}\right).\dfrac{\sqrt{x}-3}{2}\left(x\ge0;x\ne9\right)\) 

\(B=\dfrac{\left(\sqrt{x}-3\right)\left(\sqrt{x}-3\right)+\left(\sqrt{x}+3\right)\left(\sqrt{x}+3\right)+14}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}.\dfrac{\sqrt{x}-3}{2}\)

\(B=\dfrac{x-3\sqrt{x}-3\sqrt{x}+9+x+3\sqrt{x}+3\sqrt{x}+9+14}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}.\dfrac{\sqrt{x}-3}{2}\)

\(B=\dfrac{32}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}.\dfrac{\sqrt{x}-3}{2}\)

\(B=\dfrac{16}{\sqrt{x}+3}\)