a: \(=\dfrac{1}{x}-\dfrac{1}{x+1}+\dfrac{1}{x+1}-\dfrac{1}{x+2}+...+\dfrac{1}{x+2022}-\dfrac{1}{x+2023}\)
\(=\dfrac{1}{x}-\dfrac{1}{x+2023}=\dfrac{2023}{x\left(x+2023\right)}\)
b: \(=\dfrac{1}{x+1}-\dfrac{1}{x+2}+\dfrac{1}{x+2}+...+\dfrac{1}{x+2021}-\dfrac{1}{x+2022}+\dfrac{1}{x+2022}\)
=1/x+1


