Question

Answer 1

a: ĐKXĐ: 2x-5<>0

=>x<>5/2

b: ĐKXĐ; x^2-4x<>0

=>x<>0 và x<>4

Answer 2

\(\text{a)ĐKXĐ:2x-5}\ne0\)

\(\Rightarrow2x\ne5\)

\(\Rightarrow x\ne\dfrac{5}{2}\)

\(b)\dfrac{x}{x^2-4x}=\dfrac{x}{x\left(x-4\right)}\)

\(\text{ĐKXĐ:}\left[{}\begin{matrix}x\ne0\\x-4\ne0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x\ne0\\x\ne4\end{matrix}\right.\)