đặt x/4=y/3=z/2=k
=>x=4k; y=3k; z=2k
x^2-y^2-z^2=4
=>16k^2-9k^2-4k^2=4
=>3k^2=4
=>k^2=4/3
TH1: k=2/căn 3
=>\(x=\dfrac{8}{\sqrt{3}};y=\dfrac{6}{\sqrt{3}}=2\sqrt{3};z=\dfrac{4}{\sqrt{3}}\)
TH2: k=-2/căn 3
=>\(\Leftrightarrow x=-\dfrac{8}{\sqrt{3}};y=-2\sqrt{3};z=-\dfrac{4}{\sqrt{3}}\)