Bài 6:
a: \(=\dfrac{x+2}{5}-\dfrac{x-2}{15}\)
\(=\dfrac{3x+6-x+2}{15}=\dfrac{2x+8}{15}\)
b: \(=\dfrac{18x+8x-4+6-3x}{60}=\dfrac{23x+2}{60}\)
c: \(=\dfrac{x+1}{2\left(x-1\right)}-\dfrac{x^2+3}{2\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{x^2+2x+1-x^2-3}{2\left(x-1\right)\left(x+1\right)}=\dfrac{2x-2}{2\left(x-1\right)\left(x+1\right)}=\dfrac{1}{x+1}\)
d: \(=\dfrac{1-4x+4x^2-4x^2+1}{2x\left(1-2x\right)}=\dfrac{-4x+2}{2x\left(1-2x\right)}=\dfrac{-2\left(2x-1\right)}{-2x\left(2x-1\right)}=\dfrac{1}{x}\)
Đúng 0
Bình luận (0)
