Question

Answer 1

ĐKXĐ: x<>0; x<>2; x<>-2; x<>3

\(P=\left(\frac{2+x}{2-x}+\frac{4x^2}{x^2-4}-\frac{2-x}{2+x}\right):\frac{x^2-3x}{2x+x^2}\)

\(=\left(\frac{-\left(x+2\right)^2+4x^2+\left(x-2\right)^2}{\left(x-2\right)\left(x+2\right)}\right)\cdot\frac{x\left(x+2\right)}{x\left(x-3\right)}\)

\(=\frac{-x^2-4x-4+4x^2+x^2-4x+4}{x-2}\cdot\frac{1}{x-3}=\frac{4x^2-8x}{x-2}\cdot\frac{1}{x-3}\)

\(=\frac{4x\left(x-2\right)}{x-2}\cdot\frac{1}{x-3}=\frac{4x}{x-3}\)