4: \(=\dfrac{7}{5}\left(23+\dfrac{1}{4}-13-\dfrac{1}{4}\right)=10\cdot\dfrac{7}{5}=14\)
5: \(=\left(\dfrac{12+8-3}{12}\right)\cdot\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\)
\(=\dfrac{17}{12}\cdot\dfrac{1}{400}=\dfrac{17}{4800}\)
6: \(=\dfrac{5}{3}\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)=\dfrac{5}{3}\cdot12=20\)
4. \(23\dfrac{1}{4}\cdot\dfrac{7}{5}-13\dfrac{1}{4}:\dfrac{5}{7}=\dfrac{93}{4}\cdot\dfrac{7}{5}-\dfrac{53}{4}:\dfrac{5}{7}=\dfrac{651}{20}-\dfrac{371}{20}=\left(-14\right)\)
5. \(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right)\cdot\left(0,8-\dfrac{3}{4}\right)^2=\dfrac{17}{12}\cdot\dfrac{1}{400}=\dfrac{17}{1480}\)
6. \(16\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}=\dfrac{114}{7}:\left(-\dfrac{3}{5}\right)+\dfrac{198}{7}:\dfrac{3}{5}=-\dfrac{190}{7}+\dfrac{330}{7}=20\)
