Question

Answer 1

1: \(=\dfrac{4x-1-7x+1}{3x^2y}=\dfrac{-3x}{3x^2y}=\dfrac{-1}{xy}\)

2: \(=\dfrac{3x-x+6}{x\left(2x+6\right)}=\dfrac{1}{x}\)

3: \(=\dfrac{-x-1+2x}{\left(x-1\right)\left(x+1\right)}=\dfrac{x-1}{\left(x-1\right)\left(x+1\right)}=\dfrac{1}{x+1}\)

5: \(=\dfrac{5\left(x+2\right)}{4\left(x-2\right)}\cdot\dfrac{-2\left(x-2\right)}{x+2}=\dfrac{-10}{4}=-\dfrac{5}{2}\)

8: \(=\dfrac{4y^2}{-8y}\cdot\dfrac{3x^2}{11x^4}=-\dfrac{3}{11x^2}\cdot\dfrac{1}{2}y=-\dfrac{3y}{22x^2}\)

Answer 2

a,\(\dfrac{4x-1-7x+1}{3x^2y}=\dfrac{-3x}{3x^2y}=\dfrac{-1}{xy}\)