a: ĐKXĐ: x<>1; x<>-1
\(A=\dfrac{x^2-x+x+1+2x}{\left(x-1\right)\left(x+1\right)}\cdot\dfrac{x}{x+1}=\dfrac{\left(x+1\right)^2}{\left(x+1\right)^2}\cdot\dfrac{x}{x-1}=\dfrac{x}{x-1}\)
b: Khi x=3/5 thì \(A=\dfrac{3}{5}:\dfrac{-2}{5}=\dfrac{-3}{2}\)
c: Để A nguyên thì x-1+1 chia hết cho x-1
=>\(x-1\in\left\{1;-1\right\}\)
hay \(x\in\left\{-2\right\}\)


