\(\Leftrightarrow\left(x-\dfrac{3}{5}\right)^2=\dfrac{3^7}{24}:\dfrac{3^3}{6}=\dfrac{3^7}{3^3}\cdot\dfrac{6}{24}=\dfrac{3^4}{4}=\left(\dfrac{9}{2}\right)^2\)
=>x-3/5=9/2 hoặc x-3/5=-9/2
=>x=51/10 hoặc x=-39/10
\(\left(\dfrac{3}{5}-x\right)^2.\dfrac{3^3}{\left|-6\right|}=\dfrac{3^7}{24}\\ =>\left(\dfrac{3}{5}-x\right)^2=\dfrac{3^7}{24}:\dfrac{3^3}{6}\\ =>\left(\dfrac{3}{5}-x\right)^2=\dfrac{3^7}{24}\times\dfrac{6}{3^3}\\ =>\left(\dfrac{3}{5}-x\right)^2=\dfrac{3^4}{4}\\ =>\left(\dfrac{3}{5}-x\right)^2=\dfrac{81}{4}\\ =>\left[{}\begin{matrix}\dfrac{3}{5}-x=\dfrac{9}{2}\\\dfrac{3}{5}-x=-\dfrac{9}{2}\end{matrix}\right.=>\left[{}\begin{matrix}x=-\dfrac{39}{10}\\x=\dfrac{51}{10}\end{matrix}\right.\)
\(\left(\dfrac{3}{5}-x\right)^2.\dfrac{3^3}{\left|-6\right|}=\dfrac{3^7}{24}\\ \left(\dfrac{3}{5}-x\right)^2.\dfrac{27}{6}=\dfrac{2187}{24}\\ \left(\dfrac{3}{5}-x\right)^2=\dfrac{2187}{24}:\dfrac{27}{6}\\ \left(\dfrac{3}{5}-x\right)^2=\dfrac{81}{4}\\ \left(\dfrac{3}{5}-x\right)^2=\left(\dfrac{9}{2}\right)^2\\ \dfrac{3}{5}-x=\dfrac{9}{2}\\ x=\dfrac{3}{5}-\dfrac{9}{2}\\ x=-\dfrac{39}{10}\)
