Question

Answer 1

`1)`

`a)5x^2(3x^2-7x+2)=15x^4-35x^3+10x^2`

`b)(6x^3-7x^2-x+2):(2x+1)`

`=(6x^3+3x^2-10x^2-5x+4x+2):(2x+1)`

`=(2x+1)(3x^2-5x+2):(2x+1)=3x^2-5x+2`

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`2)`

`a)2x(x^2-4)=0`

`<=>x(x-2)(x+2)=0`

`<=>[(x=0),(x=+-2):}`

`b)(x+2)^2-(x-2)(x+2)=0`

`<=>(x+2)(x+2-x+2)=0`

`<=>x+2=0`

`<=>x=-2`

Answer 2

Bài 2: 

a: =>x(x-2)(x+2)=0

=>\(x\in\left\{0;2;-2\right\}\)

c: =>(x+2)(x+2-x+2)=0

=>x+2=0

=>x=-2