ĐKXĐ: \(a>0;a\ne4\)
\(A=\left(\dfrac{\sqrt{a}-2}{\left(\sqrt{a}-2\right)\left(\sqrt{a}+2\right)}+\dfrac{\sqrt{a}+2}{\left(\sqrt{a}-2\right)\left(\sqrt{a}+2\right)}\right).\dfrac{a-4}{\sqrt{a}\left(\sqrt{a}+1\right)}\)
\(=\dfrac{2\sqrt{a}}{a-4}.\dfrac{a-4}{\sqrt{a}\left(\sqrt{a}+1\right)}=\dfrac{2}{\sqrt{a}+1}\)

