a, Ta có: \(n_{H_2}=0,3\left(mol\right)\)
PT: \(A+2HCl\rightarrow ACl_2+H_2\)
Theo PT: \(n_A=n_{H_2}=0,3\left(mol\right)\)
\(\Rightarrow M_A=\dfrac{19,5}{0,3}=65\left(g/mol\right)\)
→ A là Zn.
b, Theo PT: \(n_{HCl}=2n_{H_2}=0,6\left(mol\right)\)
\(\Rightarrow m_{HCl}=0,6.36,5=21,9\left(g\right)\)
