Question

Answer 1

\(=\dfrac{3}{4}:3-\dfrac{28}{25}\cdot\dfrac{6}{7}+\dfrac{9}{7}\cdot\dfrac{14}{15}\)

\(=\dfrac{1}{4}-\dfrac{24}{25}+\dfrac{6}{5}=\dfrac{49}{100}\)

Answer 2

Trị tuyệt đối \(\dfrac{-3}{4}:\sqrt{9}-1,12\sqrt{\dfrac{36}{49}}+1\dfrac{2}{7}.\dfrac{14}{15}\)

= \(\dfrac{3}{4}:3-1,12.\dfrac{6}{7}+\dfrac{9}{7}.\dfrac{14}{15}\)

= \(\dfrac{3}{4}.\dfrac{1}{3}-\dfrac{28}{25}.\dfrac{6}{7}+\dfrac{9}{7}.\dfrac{14}{15}\)

= \(\dfrac{1}{4}-\dfrac{24}{25}+\dfrac{6}{5}\)

\(=\dfrac{-71}{100}+\dfrac{6}{5}\)

= \(\dfrac{49}{100}\)