a: ĐKXĐ: x<>3; x<>-3
b: \(B=\dfrac{\left(x-3\right)^2}{5\left(x-3\right)\left(x+3\right)}=\dfrac{x-3}{5\left(x+3\right)}\)
c: KHi x=-2/3 thì \(B=\dfrac{-\dfrac{2}{3}-3}{5\left(-\dfrac{2}{3}+3\right)}=\dfrac{-11}{3}:\left(5\cdot\dfrac{7}{3}\right)=\dfrac{-11}{3}:\dfrac{35}{3}=-\dfrac{11}{35}\)


