\(=\dfrac{-8}{3}\cdot\dfrac{2}{11}-\dfrac{8}{3}\cdot\dfrac{9}{11}=\dfrac{-8}{3}\left(\dfrac{2}{11}+\dfrac{9}{11}\right)=-\dfrac{8}{3}\)
\(-\dfrac{8}{3}.\dfrac{2}{11}-\dfrac{8}{3}:\dfrac{11}{9}=-\dfrac{8}{3}.\left(\dfrac{2}{11}+\dfrac{9}{11}\right)=-\dfrac{8}{3}.1=-\dfrac{8}{3}\)
\(b, \dfrac{-8}{3}.\dfrac{2}{11}-\dfrac{8}{3}:\dfrac{11}{9}=\dfrac{-8}{3}.\dfrac{2}{11}+\dfrac{-8}{3}.\dfrac{9}{11}=\dfrac{-8}{3}.\left(\dfrac{2}{11}+\dfrac{9}{11}\right)=\dfrac{-8}{3}.1=\dfrac{-8}{3}\)
