a) 12 - |3x - 5| = 2
|3x - 5| = 12 - 2
|3x - 5| = 10
3x - 5 = 10 và 3x - 5 = -10
*) 3x - 5 = 10
3x = 10 + 5
3x = 15
x = 15 : 3
x = 5
*) 3x - 5 = -10
3x = -10 + 5
3x = -5
x = -5/3
Vậy x = -5/3; x = 5
b) 5/x = x/80
x² = 5.80
x² = 40
x = 20 hoặc x = -20
a.12-|3x-5|=2
|3x-5|=12-2=10
⇒3x-5=10;3x-5=-10
+3x-5=10
3x=10+5=15
x=15:3=5
+3x-5=-10
3x=-10+5=-5
x=-5:3=5/3
b.5/x=x/80
⇒5.80=x2
⇒400=x2
⇒202=x2
⇒x=20
`a) 12-|3x-5| =2`
`<=> |3x-5| = 12-2 =10`
`=> [(3x-5=10),(3x-5 =-10):}`
`<=> [(3x=10+5=15),(3x=-10+5=-5):}`
`<=>[(x=15/3 =5),(x=-5/3):}`
Vậy `x in {5;-5/3}`
`b) 5/x = x/80 `
`<=> x^2 = 400`
`=> [(x=20),(x=-20):}`
Vậy `x = +- 200`