89:
a: \(A=\dfrac{3x^3-2x^2+15x^2-10x+3x-2+7}{3x-2}=x^2+5x+1+\dfrac{7}{3x-2}\)
A nguyên thì 3x-2 thuộc Ư(7)
=>3x-2=7 hoặc 3x-2=1
=>x=1; x=3
b: \(B=\dfrac{x^3\left(2x^2-7\right)+4x^4-14x^2+14x^2-49+5}{2x^2-7}\)
\(=x^3+2x^2+7+\dfrac{5}{2x^2-7}\)
B nguyên
=>2x^2-7=-5 hoặc 2x^2-7=1
=>\(x\in\left\{1;-1;2;-2\right\}\)