Ta có: \(n_{Na}=\dfrac{46}{23}=2\left(mol\right)\)
PT: \(2Na+2H_2O\rightarrow2NaOH+H_2\)
_____2______2________2_____1 (mol)
a, \(V_{H_2\left(A\right)}=1.22,4=22,4\left(l\right)\)
b, Ta có: m dd sau pư = 46 + 1000 - 1.2 = 1044 (g)
\(\Rightarrow C\%_{NaOH}=\dfrac{2.40}{1044}.100\%\approx7,66\%\)
c, \(D_{ddB}=\dfrac{1044}{966}\approx1,08\left(g/ml\right)\)
