Question

Answer 1

Bài 2: 

a: \(3A=3^2+3^3+...+3^{2023}\)

=>\(2A=3^{2023}-3\)

=>\(3^x-3=3^{2023}-3\)

=>x=2023

b: \(2B=2^2+2^3+...+2^{101}\)

=>\(B=2^{101}-2\)

\(2^{2x+1}-2=B\)

=>\(2^{2x+1}=2^{101}\)

=>2x+1=101

=>x=50

d: \(\Leftrightarrow5^{3x+3}=5^{18}\)

=>3x+3=18

=>x=5

e: \(A=2^x+2^{x+1}+...+2^{x+2020}\)

\(\Leftrightarrow2A=2^{x+1}+2^{x+2}+...+2^{x+2021}\)

=>\(A=2^{x+2021}-2^x\)

=>\(A=2^{2024}-2^3\)

=>\(x+2021=2024\)

=>x=3