11: \(\Leftrightarrow x^3+6x^2+12x+8=27\)
=>(x+2)^3=27
=>x+2=3
=>x=1
12: \(\Leftrightarrow\left(x+4\right)\left(3-x\right)=0\)
=>x=3 hoặc x=-4
13: \(\Leftrightarrow x\left(7x^2+12x+5\right)=0\)
=>x(7x+5)(x+1)=0
=>\(x\in\left\{0;-1;-\dfrac{5}{7}\right\}\)
14: =>3(x-1)^2=0
=>x=1


