`|2/3 -1/3:x| - 5/6=-1/3`
`|2/3 -1/3:x| =-1/3+5/6`
`|2/3 -1/3:x| =-2/6+5/6`
`|2/3 -1/3:x| =1/2`
`@Th1:`
`2/3-1/3:x=1/2`
`1/3:x=2/3-1/2`
`1/3:x=4/6-3/6`
`1/3:x=1/6`
`x=1/3:1/6`
`x=1/3 xx 6`
`x=2`
`@Th2:`
`2/3-1/3:x=-1/2`
`1/3:x=2/3-(-1/2)`
`1/3:x=2/3+1/2`
`1/3:x=4/6+3/6`
`1/3:x=7/6`
`x=1/3:7/6`
`x=1/3 x 6/7`
`x=2/7`
Vậy `x={2;2/7}`
`|2/3 - 1/3 : x| = -1/3 + 5/6`
`|2/3 - 1/3 : x| = 1/2`
`->` \(\left[{}\begin{matrix}\dfrac{2}{3}-\dfrac{1}{3}:x=\dfrac{1}{2}\\\dfrac{2}{3}-\dfrac{1}{3}:x=-\dfrac{1}{2}\end{matrix}\right.\)
`->` \(\left[{}\begin{matrix}x=2\\x=\dfrac{2}{7}\end{matrix}\right.\)
=>|2/3-1/3:x|=-1/3+5/6=5/6-2/6=1/2
=>2/3-1/3:x=1/2 hoặc 2/3-1/3:x=-1/2
=>x=2 hoặc x=2/7
