Question

Answer 1

`= (9/5)^5 xx (-20/27)^5`

`= 9/5 xx -20/27`

`= -4/3`

`b,, = 3^3 xx 3^(-2)`

`= 3`.

Answer 2

`(9/5)^5 : (27/-20)^5`

`= (9/5)^5 . (-20/27)^5`

`= [9/5 xx (-20/27)]^5`

`= (-4/3)^5`

`= -1024/243`

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`3^3 xx 9^(-1)`

\(=3^3.3^{2.\left(-1\right)}\)

\(=3^3.3^{-2}\)

 \(=3^{3+\left(-2\right)}\)

\(=3^1=3\)