\(\dfrac{\sqrt{6^5}}{\sqrt{2^3\cdot3^5}}=\dfrac{\sqrt{6^3}\cdot\sqrt{6^2}}{\sqrt{6^3}\cdot\sqrt{3^2}}=\dfrac{6}{3}=2\)
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\(=\dfrac{\sqrt{7776}}{\sqrt{8.243}}=\dfrac{\sqrt{7776}}{\sqrt{1944}}=\dfrac{36\sqrt{6}}{18\sqrt{6}}=\dfrac{36}{18}=2\)
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