24, \(A=\sqrt{13+2.2\sqrt{3}}=\sqrt{\left(2\sqrt{3}+1\right)^2}=2\sqrt{3}+1\)
\(B=\dfrac{2\sqrt{3+2\sqrt{3}+1}}{\sqrt{6}-\sqrt{2}}=\dfrac{2\sqrt{\left(\sqrt{3}+1\right)^2}}{\sqrt{6}-\sqrt{2}}=\dfrac{\sqrt{2}\left(\sqrt{3}+1\right)}{\sqrt{3}-1}=\dfrac{\sqrt{2}\left(\sqrt{3}+1\right)^2}{2}=\dfrac{\sqrt{2}\left(4+2\sqrt{3}\right)}{2}=\dfrac{4\sqrt{2}+2\sqrt{6}}{2}=2\sqrt{2}+\sqrt{6}\)

