\(a,=4.\dfrac{1}{16}+25.\left(\dfrac{27}{64}:\dfrac{125}{64}\right):\dfrac{27}{8}=\dfrac{1}{4}+25.\dfrac{27}{125}:\dfrac{27}{8}=\dfrac{1}{4}+25.\dfrac{8}{125}=\dfrac{1}{4}+\dfrac{8}{5}=\dfrac{5+32}{20}=\dfrac{37}{20}\\ b,=8+3.1-1+4:\dfrac{1}{2}-8=8+3-1+8-8=10+8-8=10\)
a: \(=4\cdot\dfrac{1}{16}+25\cdot\left[\left(\dfrac{3}{4}:\dfrac{5}{4}\right)^3\right]:\left(\dfrac{3}{2}\right)^3\)
\(=\dfrac{1}{4}+25\cdot\left(\dfrac{3}{5}\right)^3:\left(\dfrac{3}{2}\right)^3\)
\(=\dfrac{1}{4}+25\cdot\left(\dfrac{3}{5}:\dfrac{3}{2}\right)^3\)
\(=\dfrac{1}{4}+25\cdot\left(\dfrac{2}{5}\right)^3\)
\(=\dfrac{1}{4}+25\cdot\dfrac{8}{125}=\dfrac{1}{4}+\dfrac{8}{5}=\dfrac{5+32}{20}=\dfrac{37}{20}\)
b: \(=8+3-1+\left[4\cdot2\right]-8\)
=2+8
=10
a) \(4.\left(\dfrac{1}{4}\right)^2+25\left[\left(\dfrac{3}{4}\right)^3:\left(\dfrac{5}{4}\right)^3\right]:\left(\dfrac{3}{2}\right)^3\)
\(=2^2.\left(\dfrac{1}{4}\right)^2+25\left[\left(\dfrac{3}{4}:\dfrac{5}{4}\right)^3\right]:\left(\dfrac{3}{2}\right)^3\)
\(=\left(\dfrac{1}{4}\right)^2+25.\left(\dfrac{3}{5}\right)^3:\left(\dfrac{3}{2}\right)^3\)
\(=\dfrac{1}{16}+25.\left(\dfrac{2}{5}\right)^3\)
\(=\dfrac{1}{16}+\dfrac{25.8}{125}\)
\(=\dfrac{1}{16}+\dfrac{200}{125}=\dfrac{133}{80}\)
b) \(2^3+3\left(\dfrac{1}{2}\right)^0-1+\left[\left(-2\right)^2:\dfrac{1}{2}\right]-8\)
\(=8+3.1-1+4:\dfrac{1}{2}-8\)
\(=8+3-1+8-8\)
\(=10\)
