a) \(5x^3=-40\Rightarrow x^3=-8=\left(-2\right)^3\Rightarrow x=-2\)
b) \(\left(8\dfrac{1}{2}x-5\right)^3=125=5^3\)\(\Rightarrow\dfrac{17}{2}x-5=5\Rightarrow\dfrac{17}{2}x=10\Rightarrow x=\dfrac{20}{17}\)
c) \(2.9^{x-1}=\dfrac{2}{9}\Rightarrow2.9^x=2\Rightarrow9^x=1\Rightarrow x=0\)
d) \(\left(x+\dfrac{2021}{2022}\right)^6=0\Rightarrow x+\dfrac{2021}{2022}=0\Rightarrow x=-\dfrac{2021}{2022}\)
a: =>x3=-8
=>x=-2
b: =>17/2x-5=5
=>17/2x=10
=>x=10:17/2=20/17
c: =>9x-2=1/9
=>x-2=-1
=>x=1
d: =>x+2021/2022=0
hay x=-2021/2022
(8 và 1/2x-5)^3 = 125
=>(17/2x-5)^3=5^3
=>17/2x-5=5
=>17/2x=10
x=10:17/2
x=20/17