Ta có: \(A=1-\frac12+\frac13-\frac14+\frac15-\frac16+\frac17-\frac18+\frac19-\frac{1}{10}\)
\(=1+\frac12+\cdots+\frac{1}{10}-2\left(\frac12+\frac14+\cdots+\frac{1}{10}\right)\)
\(=1+\frac12+\cdots+\frac{1}{10}-1-\frac12-\cdots-\frac15\)
\(=\frac16+\frac17+\frac18+\frac19+\frac{1}{10}\)
=B