\(\left(x-2\right)^2=\dfrac{9}{25}->\left(x-2\right)^2=\left(\dfrac{3}{5}\right)^2\)
\(->x-2=\dfrac{3}{5}->x=\dfrac{3}{5}+2=\dfrac{13}{5}\)
(x - 2)² = 9/25
x - 2 = 3/5 hoặc x - 2 = -3/5
*) x - 2 = 3/5
x = 3/5 + 2
x = 13/5
*) x - 2 = -3/5
x = -3/5 + 2
x = 7/5
Vậy x = 13/5; x = 7/5

