1: \(=\dfrac{1}{7}\left(\dfrac{1}{3}+\dfrac{1}{2}-1\right)=\dfrac{1}{7}\cdot\dfrac{-1}{6}=\dfrac{-1}{42}\)
2: \(=\dfrac{3}{5}\left(\dfrac{7}{9}+\dfrac{2}{9}\right)+\dfrac{3}{5}=\dfrac{3}{5}+\dfrac{3}{5}=\dfrac{6}{5}\)
3: \(=\dfrac{21}{7}-\dfrac{21}{5}+19=3+19-\dfrac{21}{5}=22-4.2=17.8\)
