a: \(A=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{16}-\dfrac{1}{17}=\dfrac{15}{34}\)
b: \(4B=1+\dfrac{1}{4}+...+\dfrac{1}{256}\)
\(\Leftrightarrow B\cdot\dfrac{3}{4}=1-\dfrac{1}{1024}=\dfrac{1023}{1024}\)
=>B=341/256
`a, = 1/(2.3) + 1/(3.4) + ... + 1/(16 xx 17)`
`= 1/2 - 1/3 + 1/3 - 1/4 + ... +1/16 - 1/17`
`= 16/34 = 8/17`
`b, = (256 + 64 + 16 + 4 + 1)/1024`
`= 341/1024`