\(5=\sqrt{25}>\sqrt{24}=2\sqrt{6}\)
\(4=\sqrt{16}< \sqrt{19}\)
\(4\sqrt{3}=\sqrt{48}< \sqrt{49}=7\)
`3\sqrt{10}=\sqrt{3^2 .10}=\sqrt{90}`
`4\sqrt{5}=\sqrt{4^2 .5}=\sqrt{80}`
Vì `90 > 80<=>\sqrt{90} > \sqrt{80}` Hay `3\sqrt{10} > 4\sqrt{5}`
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`3\sqrt{2}=\sqrt{3^2 .2}=\sqrt{18}`
`2\sqrt{3}=\sqrt{2^2 .3}=\sqrt{12}`
Vì `18 > 12<=>\sqrt{18} > \sqrt{12}` Hay `3\sqrt{2} > 2\sqrt{3}`
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`2+\sqrt{6}` `5=2+3=2+\sqrt{9}`
Vì `6 < 9<=>2+\sqrt{6} < 2+\sqrt{9}` Hay `2+\sqrt{6} < 5`
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`7-2\sqrt{2}=7-\sqrt{2^2 .2}=7-\sqrt{8}`
`4=7-3=7-\sqrt{9}`
Vì `8 < 9<=>7-\sqrt{8} < 7-\sqrt{9}`
Hay `7-2\sqrt{2} < 4`
Vì Hay
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Vì Hay


