Question

Answer 1

e: \(\dfrac{20}{28}-\dfrac{18}{84}=\dfrac{60-18}{84}=\dfrac{42}{84}=\dfrac{1}{2}\)

i: \(\dfrac{11}{4}-2=\dfrac{11}{4}-\dfrac{8}{4}=\dfrac{3}{4}\)

g: \(\dfrac{8}{12}-\dfrac{8}{24}=\dfrac{1}{3}-\dfrac{1}{6}=\dfrac{1}{6}\)

Answer 2

e.\(\dfrac{20}{28}-\dfrac{18}{84}=\dfrac{20\times3}{28\times3}-\dfrac{18}{84}=\dfrac{60-18}{84}=\dfrac{42}{84}=\dfrac{1}{2}\)

e.\(\dfrac{11}{4}-2=\dfrac{11-8}{4}=\dfrac{3}{4}\)

g.\(\dfrac{8}{12}-\dfrac{8}{24}=\dfrac{16-8}{24}=\dfrac{8}{24}=\dfrac{1}{3}\)

`@V.Tr.V`

Answer 3

e,20/28-18/84

=5/7-3/14

=10/14-3/14

=7/14

=1/2

i,11/4-2

=11/4-8/4

=3/4

g,8/12-8/24

=16/24-8/24

=8/24

=1/3

Answer 4

\(e,\dfrac{10}{ 14}-\dfrac{3}{14}=\dfrac{10-3}{14}=\dfrac{7}{14}=\dfrac{1}{2}\)

\(g,\dfrac{8}{12}-\dfrac{4}{12}=\dfrac{8-4}{12}=\dfrac{4}{12}=\dfrac{1}{3}\)

\(i,\dfrac{11}{4}-\dfrac{8}{4}=\dfrac{11-8}{4}=\dfrac{3}{4}\)