Question

Answer 1

a: \(M=-\left(\left|x+3\right|+y^2-10y-7\right)\)

\(=-\left(\left|x+3\right|+y^2-10y+25-32\right)\)

\(=-\left|x+3\right|-\left(y-5\right)^2+32< =32\)

Dấu '=' xảy ra khi x=-3 và y=5

b: \(N=-\left[\left(x+8\right)^{26}+y^2+14y-8\right]\)

\(=-\left[\left(x+8\right)^{26}+y^2+14y+49-57\right]\)

\(=-\left(x+8\right)^{26}-\left(y+7\right)^2+57< =57\)

Dấu '=' xảy ra khi x=-8và y=-7