\(x-\dfrac{4}{3}=\dfrac{5}{4}\cdot\dfrac{-19}{5}=\dfrac{-19}{4}\)
=>x=-19/4+4/3=-57/12+16/12=-41/12
x - 4/3 = 5/4 . (-19/5)
x - 4/3 = -19/4
x = -19/4 + 4/3
x = -41/12
\(x-\dfrac{4}{3}=\dfrac{5}{4}.\left(\dfrac{1}{5}-4\right)\\ x-\dfrac{4}{3}=\dfrac{5}{4}.\left(\dfrac{-19}{5}\right)\\ x-\dfrac{4}{3}=\dfrac{-19}{4}\\ x=\dfrac{-19}{4}+\dfrac{4}{3}\\ x=\dfrac{-41}{12}\)
Vậy \(x=\dfrac{-41}{12}\)
x-4/3=5/4 x -19/5
x-4/3=-19/4
x=-19/4+4/3
x=-57/12+16/12
x=-41/12
