Question

Answer 1

a: (3x-2)(4x+5)=0

=>3x-2=0 hoặc 4x+5=0

=>x=2/3 hoặc x=-5/4

b: \(\Leftrightarrow\dfrac{x\left(x+2\right)-\left(x-2\right)}{x\left(x-2\right)}=\dfrac{2}{x\left(x-2\right)}\)

=>x²+2x-x+2=2

=>x(x+1)=0

=>x=-1

Answer 2

`(3x-2)(4x-5) = 0`

`=> 3x - 2 = 0`

      `4x - 5 = 0`

`=> x = 2/3`.

      `x = 5/4`.

Vậy `S = {2/3; 5/4}`

b, `(x+2)/(x-2) - 1/x = 2/(x(x-2))`

Đk: `x ne 2, 0`.

`=> (x^2 + 2x - x + 2)/(x(x-2)) = 2/(x(x-2))`

`=> x^2 + x + 2 = 2`

`=> x^2 + x = 0`

`=> x(x+1) = 0`

`=> x = 0`

     `x + 1 = 0`

`=> x = 0.`

      `x = -1`.