Question

Answer 1

Câu 2:

a: 2x-3=3(x-1)+x+2

=>3x-3+x+2=2x-3

=>4x-1=2x-3

=>4x-2x=-3+1

=>2x=-2

=>x=-1

b: 2x-5=0

=>2x=5

=>\(x=\frac52\)

c: 2x-7=11x+11

=>11x-2x=-7-11

=>9x=-18

=>x=-2

d: ĐKXĐ: y∉{2;-2}

Ta có: \(\frac{y+1}{y-2}-\frac{5}{y+2}=\frac{12}{y^2-4}+1\)

=>\(\frac{\left(y+1\right)\left(y+2\right)-5\left(y-2\right)}{\left(y-2\right)\left(y+2\right)}=\frac{12+y^2-4}{\left(y-2\right)\left(y+2\right)}\)

=>\(\left(y+1\right)\left(y+2\right)-5\left(y-2\right)=y^2+8\)

=>\(y^2+3y+2-5y+10=y^2+8\)

=>-2y+12=8

=>-2y=-4

=>y=2(loại)