Bài 8:
Ta có: \(n_{Al}=\dfrac{5,4}{27}=0,2\left(mol\right)\)
PT: \(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
____0,2_____0,3_______0,1______0,3 (mol)
a, \(V_{H_2}=0,3.22,4=6,72\left(l\right)\)
b, \(m_{H_2SO_4}=0,3.98=29,4\left(g\right)\Rightarrow C\%_{H_2SO_4}=\dfrac{29,4}{200}.100\%=14,7\%\)
c, Có: m dd sau pư = 5,4 + 200 - 0,3.2 = 204,8 (g)
\(\Rightarrow C\%_{Al_2\left(SO_4\right)_3}=\dfrac{0,1.342}{204,8}.100\%\approx16,7\%\)
Bạn tham khảo nhé!
