Bài 5:
a, \(m_{NaCl}=50.15\%=7,5\left(g\right)\)
b, \(m_{ddNaOH}=\dfrac{4}{10\%}=40\left(g\right)\)
c, Có: \(n_{Al}=\dfrac{6,48}{27}=0,24\left(mol\right)\)
PT: \(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
___0,24_0,18____0,12 (mol)
⇒ VO2 = 0,18.22,4 = 4,032 (l)
mAl2O3 = 0,12.102 = 12,24 (g)
d, \(n_{Fe_2O_3}=\dfrac{16}{160}=0,1\left(mol\right)\)
PT: \(Fe_2O_3+3H_2\underrightarrow{t^o}2Fe+3H_2O\)
_____0,1_________0,2 (mol)
\(\Rightarrow n_{Fe}=0,2.56=11,2\left(g\right)\)
Bạn tham khảo nhé!
