Question

Answer 1

\(\left(9x-4\right)\left(x-\dfrac{1}{2}\right)-\left(x-\dfrac{1}{2}\right)\left(6-x\right)=0\)

\(\Rightarrow\left(x-\dfrac{1}{2}\right)\left(9x-4-6+x\right)\)

\(\Rightarrow\left(x-\dfrac{1}{2}\right)\left(10x-10\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=0\\10x-10=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=1\end{matrix}\right.\)

Vậy \(x=\dfrac{1}{2};x=10\)