a) \(\dfrac{3}{5}+\dfrac{2}{3}\times\dfrac{4}{5}=\dfrac{3}{5}+\dfrac{8}{15}=\dfrac{9}{15}+\dfrac{8}{15}=\dfrac{17}{15}\)
b) \(\dfrac{4}{9}-\dfrac{3}{14}:\dfrac{4}{7}=\dfrac{4}{9}-\dfrac{3}{14}\times\dfrac{7}{4}=\dfrac{4}{9}-\dfrac{3}{8}=\dfrac{32}{72}-\dfrac{27}{72}=\dfrac{5}{72}\)
